^ I liked the proof I heard for 0!.
If 3! = 3*2*1 = 6, and 2! = 2*1 = 2, then 2! can also be expressed as 3!/3. Thus any n! = (n+1)!/(n+1), which is a rather redundant thing to say since really n! is just the product of all the numbers from 1 to n, right?
But what about 0!?! (Will Zeke kill me for that?) Multiplying the numbers from 1 to 0 implies the answer would either be 0, or undefined if 1 must increment. But using the other formula, we see that 0! = (0+1)!/(0+1) = 1!/1 = 1. And sure enough, 0! = 1. But I've always found that proof kind of silly.
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"Please, Aslan," said Lucy, "what do you call soon?"
"I call all times soon," said Aslan; and instantly he vanished away and Lucy was alone with the Magician.
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